X^2+2.333x-2=0

Solution for X^2+2.333x-2=0 equation:

X^2+2.333X-2=0

a = 1; b = 2.333; c = -2;
Δ = b2-4ac
Δ = 2.3332-4·1·(-2)
Δ = 13.442889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.333)-\sqrt{13.442889}}{2*1}=\frac{-2.333-\sqrt{13.442889}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.333)+\sqrt{13.442889}}{2*1}=\frac{-2.333+\sqrt{13.442889}}{2}
$